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GCSE Chemistry · AQA 8462 · Topic 4.3.2

Use of amount of substance in relation to masses of pure substances

Key points

  • (Higher) Chemical amounts are measured in moles (mol). One mole of a substance has a mass in grams equal to its ArA_r or MrM_r.
  • The Avogadro constant is 6.02×10236.02 \times 10^{23} particles per mole.
  • Key equation: number of moles=mass (g)Mr\text{number of moles} = \frac{\text{mass (g)}}{M_r}, e.g. 88 g of CO2CO_2 (MrM_r 44) is 2 mol.
  • A balanced equation shows the mole ratio of reactants and products, so you can calculate the mass of product from a given mass of reactant.
  • You can work out a balanced equation from masses: convert each mass to moles, divide by the smallest number of moles to get the simplest whole-number ratio.
  • The limiting reactant is completely used up and limits the amount of product. Any other reactant is in excess. Doubling the limiting reactant doubles the product.

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The mole lets chemists count particles by weighing them. Most of this sub-topic is (Higher tier), except concentration in g/dm³, which everyone needs.

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