Skip to main content
Examonaut

A level Chemistry · Edexcel 9CH0 · Topic 12B

pH calculations

Key points

  • pH=−log⁡[H+]pH = -\log[H^+] and [H+]=10−pH[H^+] = 10^{-pH}. A change of one pH unit is a ten-fold change in [H⁺].
  • Strong acid: [H⁺] = acid concentration (for monoprotic acids).
  • Strong base: find [OH⁻], then [H+]=Kw[OH−][H^+] = \frac{K_w}{[OH^-]} with KwK_w = 1.00 × 10⁻¹⁴ mol² dm⁻⁶ at 298 K.
  • Weak acid: assume [H⁺] = [A⁻] and [HA] at equilibrium ≈ initial concentration, so [H+]=Ka×[HA][H^+] = \sqrt{K_a \times [HA]}.
  • These assumptions fail for fairly strong weak acids or very dilute solutions.
  • Pure water is neutral at all temperatures because [H⁺] = [OH⁻], even though its pH falls below 7 when warmed (ionisation is endothermic).
  • After partial neutralisation, work out excess moles of acid or base, divide by the total volume, then find pH.

Topic notesPremium

Almost every acid–base question ends in a pH. This sub-topic gives you one method for each kind of solution: strong acid, strong base, weak acid and a mixture after partial neutralisation.

Unlock the full notes with Premium

Premium includes full topic notes, the paper generator, self-quizzes and progress tracking.

Practise this topicPremium

Premium members can generate an exam-style paper with a mark scheme, or take a quick quiz, on pH calculations.

Back to all Chemistry topics